8/n^2-3/n

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Solution for 8/n^2-3/n equation: 


D( n )

n = 0

n^2 = 0

n = 0

n = 0

n^2 = 0

n^2 = 0

1*n^2 = 0 // : 1

n^2 = 0

n = 0

n in (-oo:0) U (0:+oo)

8/(n^2)-(3/n) = 0

8/(n^2)-3*n^-1 = 0

8*n^-2-3*n^-1 = 0

t_1 = n^-1

8*t_1^2-3*t_1^1 = 0

8*t_1^2-3*t_1 = 0

DELTA = (-3)^2-(0*4*8)

DELTA = 9

DELTA > 0

t_1 = (9^(1/2)+3)/(2*8) or t_1 = (3-9^(1/2))/(2*8)

t_1 = 3/8 or t_1 = 0

t_1 = 0

n^-1+0 = 0

n^-1 = 0

1*n^-1 = 0 // : 1

n^-1 = 0

n naleu017Cy do O

t_1 = 3/8

n^-1-3/8 = 0

1*n^-1 = 3/8 // : 1

n^-1 = 3/8

-1 < 0

1/(n^1) = 3/8 // * n^1

1 = 3/8*n^1 // : 3/8

8/3 = n^1

n = 8/3

n = 8/3

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